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Slide 1

Pythagoras and Triangles Problem Solving

Year 10 Mathematics NSW Curriculum Using Pythagoras' Theorem to Solve Real-World Problems

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Slide 2

Who Was Pythagoras?

Ancient Greek philosopher and mathematician (c. 570-495 BCE) Founded the Pythagorean school in ancient Greece Believed numbers were the key to understanding the universe His theorem is one of the most famous in mathematics

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Slide 3

The Pythagorean Theorem

In a right-angled triangle: a² + b² = c² a and b are the shorter sides (legs) c is the longest side (hypotenuse) Only works for right-angled triangles

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Quick Check: Identify the Hypotenuse

Look at the triangles on the board Point to the hypotenuse in each triangle Remember: it's always opposite the right angle It's always the longest side

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Slide 5

Finding the Hypotenuse

When you know both legs (a and b) Use: c = √(a² + b²) Example: If a = 3 and b = 4 Then c = √(3² + 4²) = √(9 + 16) = √25 = 5

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Slide 6

Finding a Leg

When you know the hypotenuse (c) and one leg Rearrange to: a = √(c² - b²) or b = √(c² - a²) Example: If c = 13 and b = 5 Then a = √(13² - 5²) = √(169 - 25) = √144 = 12

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Slide 7

Practice Problem

A ladder is 10 meters long It leans against a wall The base is 6 meters from the wall How high up the wall does it reach?

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Slide 8

Area of Right-Angled Triangles

Area = ½ × base × height For right triangles, use the two legs as base and height The legs are perpendicular to each other Example: legs of 6 cm and 8 cm give area = ½ × 6 × 8 = 24 cm²

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Slide 9

Pythagoras vs Area Calculations

{"left":"Pythagoras finds missing side lengths\nUses a² + b² = c²\nInvolves square roots\nGives measurements in linear units (cm, m)","right":"Area finds space inside triangle\nUses Area = ½ × base × height\nInvolves multiplication and division\nGives measurements in square units (cm², m²)"}

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Slide 10

Real-World Problem Solving

Work in pairs Choose a problem from the worksheet Decide: Do you need Pythagoras or area? Show all working clearly

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Slide 11

Surveying Applications

Surveyors use Pythagoras to measure distances Traverse offset surveys create right triangles Measure accessible distances to find inaccessible ones Essential for mapping and construction

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Slide 13

Challenge Problem

A rectangular field is 80m by 60m A path goes diagonally across it What is the length of the path? What is the area of the field?

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