Pythagoras and Trigonometry Practice
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Sketch, Label and Solve: Right-Angled Triangles
📐 Quick Reference & Triangle Labelling
SOHCAHTOA: sin θ = opposite/hypotenuse, cos θ = adjacent/hypotenuse, tan θ = opposite/adjacent
Inverse functions: θ = sin⁻¹(opp/hyp), θ = cos⁻¹(adj/hyp), θ = tan⁻¹(opp/adj)
Angle of elevation: looking UP from horizontal | Angle of depression: looking DOWN from horizontal
Reminder: Check your calculator is in DEGREE mode!
B
|\
| \
12m| \
| \
|____\
C 8m A
🔢 Finding Missing Sides and Angles
🏗️ Multi-Step Problem Solving
Answer Key
1. BC = O (opposite), AC = A (adjacent), AB = H (hypotenuse)
2. cosine (cos 35° = 8/AB, so AB = 8/cos 35°)
3. Height = 4.2 × sin 65° = 4.2 × 0.906 = 3.8m
4. Horizontal distance = 45/tan 28° = 45/0.532 = 84.6m
5. θ = tan⁻¹(7.3/11.8) = tan⁻¹(0.619) = 32°
6. Height = 15.6 × tan 42° = 15.6 × 0.900 = 14.0m
7. Min distance = 1.2/tan 8° = 1.2/0.140 = 8.6m. No, 7m < 8.6m required.
8. Additional horizontal: 150 × cos 35° = 122.9m. Total horizontal: 200 + 122.9 = 322.9m. Height: 150 × sin 35° = 86.1m
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