
Science • Year 13 • 60 • 6 students • Created with AI following Aligned with National Curriculum for England
I want a lesson plan on alternating current and voltage for a AQA A level Physics. It should include appropriate theory, worked examples, exam questions with answers
This lesson is designed for AQA A-Level Physics (Year 13) and aligns with the UK A-Level specification, specifically the "Further Mechanics and Thermal Physics" section, under the topic of "Alternating Currents."
By the end of this 60-minute lesson, students should:
Engagement Question:
Display two waveforms on the board – one a DC signal and one an AC signal. Ask:
👉 Why do we use alternating current in household electricity instead of direct current?
Encourage students to discuss in pairs for 2 minutes before taking brief responses.
🛠️ Teacher’s Explanation:
Use a sine wave diagram to introduce key AC concepts:
Root Mean Square (rms) Voltage
Power in an AC Circuit
🎯 Quick Discussion:
📌 Why don’t we use peak values when calculating power?
Problem: A UK mains socket provides 230V rms at 50 Hz. Calculate:
✍ Solution:
Using:
[
V_0 = V_{\text{rms}} \times \sqrt{2}
]
[
V_0 = 230 \times 1.414
]
[
V_0 ≈ 325V
]
For period:
[
T = \frac{1}{f} = \frac{1}{50}
]
[
T = 0.02s \quad \text{(or 20ms)}
]
Students now attempt the following AQA exam-style questions individually:
A coil in an AC circuit has an alternating voltage given by:
[
V = 240\sin(314t)
]
(a) Determine the peak voltage of the supply.
(b) State the frequency of the supply.
(c) Calculate the rms voltage.
✏️ Answers:
(a) Peak Voltage = 240V (the coefficient of sine)
(b) Given ω = 314 rad/s, use ω = 2πf to solve for f:
[
f = \frac{314}{2\pi} = 50 Hz
]
(c)
[
V_{\text{rms}} = \frac{V_0}{\sqrt{2}} = \frac{240}{1.414} ≈ 170V
]
A resistor of 10Ω is connected to a 230V rms AC supply. Calculate:
(i) The rms current through the resistor.
(ii) The average power dissipated in the resistor.
✏️ Solutions:
(i) Using Ohm’s Law (V = IR):
[
I_{\text{rms}} = \frac{V_{\text{rms}}}{R} = \frac{230}{10} = 23A
]
(ii) Power formula:
[
P = V_{\text{rms}} \times I_{\text{rms}} = 230 \times 23 = 5290W
]
🗣️ Discussion Questions:
🏆 Exit Quiz (Whiteboard or verbal recap)
(This lesson follows specific UK AQA A-Level Physics curriculum requirements and challenges students to apply mathematical reasoning to AC concepts.) 🚀
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