
Maths • Year 8 • 120 • 5 students • Created with AI following Aligned with Australian Curriculum (F-10)
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lesson is on: Understand slope and y-intercept
Students develop a meaning for gradient (slope) and the y-intercept, then connect these features to equations, tables and graphs. They use a graphing tool to test how changing parameters affects a line and apply their understanding to a practical financial context.
0–10 min · Hook and diagnostic. Teacher displays three lines and asks, “Which line represents the fastest increase, and how can you tell?” using the opening graph comparison. Students individually annotate the lines, then explain their ideas to the group; the teacher records prior vocabulary such as steepness, crossing point and rate.
10–30 min · Explicit teaching. Teacher uses the gradient and intercept explanation to introduce (y=mx+c): (m) is the gradient or rate of change, and (c) is the y-intercept, where the line crosses the y-axis. Model (y=2x+3), identifying (m=2), (c=3), plotting the intercept and moving up 2 and right 1. Students complete guided examples on the guided gradient and intercept worksheet, including (y=-x+4), (y=\frac12x-2) and (y=3).
30–45 min · Gradient from points. Teacher demonstrates (\text{gradient}=\frac{\text{change in }y}{\text{change in }x}) using two labelled points, emphasising positive, negative and zero gradients. Students calculate the gradient of three lines from diagrams, check by counting rise and run, and explain what each value means. The teacher checks understanding through targeted questions: “What does the numerator represent?” and “What would a negative gradient look like?”
45–65 min · Match and justify. Teacher distributes the Linear Graph Matching Cards and asks students to match graphs, equations, tables and descriptions of gradient, intercept and behaviour. Students work as a small team, recording matches and giving a mathematical justification for each. The teacher deliberately challenges misconceptions, including confusing the x-intercept with the y-intercept and reading the gradient as the starting value.
65–85 min · Digital investigation. Teacher opens the digital investigation instructions and demonstrates a graphing tool with sliders or editable equations for (y=mx+c). Students investigate one parameter at a time: compare (y=x+2), (y=3x+2), (y=-x+2), then compare (y=2x-3), (y=2x) and (y=2x+5). They record conjectures on the worksheet, test them digitally, and describe the effect of changing (m) and (c). Each student must state one conjecture and evidence that supports or disproves it.
85–108 min · Financial modelling task. Teacher presents a practical problem on the phone-plan modelling task: Plan A costs a $15 connection fee plus $4 per gigabyte; Plan B costs a $5 connection fee plus $6 per gigabyte. Students define (x) and (y), write (y=4x+15) and (y=6x+5), graph both relations and determine which plan is cheaper for selected data usage amounts. Students explain the meaning of each gradient and intercept, identify the approximate break-even point, and verify one calculated value by substitution.
108–120 min · Plenary and assessment. Teacher uses the final review questions for a short group discussion, then students complete the final questions on the worksheet independently. Students submit: identify (m) and (c) in (y=-2x+7), state the gradient between ((1,3)) and ((4,9)), explain the meaning of the y-intercept, and describe what changes when (c) increases.
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