
Maths • Year 8 • 60 • 25 students • Created with AI following Aligned with Australian Curriculum (F-10)
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Pythagoras theorem using it in coordinate geometric
Students apply Pythagoras’ theorem to find lengths in right-angled triangles and connect this to coordinate geometry by calculating distances on a grid. The lesson builds from recognising right angles and labelling triangle sides to using a coordinate method to solve problems.
0–6 min · Hook (notice and name). Teacher shows a coordinate grid with two points (e.g., A(1,2) and B(7,2)) and a third point C(7,6), forming a right-angled triangle, and asks students to quickly discuss: “Which segment is the hypotenuse?” Students label the right angle and predict which side is longest using the diagram.
6–16 min · Mini-teach (Pythagoras in coordinates). Teacher explicitly connects coordinate differences to triangle side lengths: horizontal change = (|\Delta x|), vertical change = (|\Delta y|), and the distance is the hypotenuse. Students copy a worked example: distance between A(1,2) and C(7,6). They compute (|\Delta x|=6), (|\Delta y|=4), then (d=\sqrt{6^2+4^2}=\sqrt{52}\approx 7.2).
16–30 min · Guided practice (three short tasks). Teacher circulates while students solve in pairs on grid paper or a worksheet, with prompts to check perpendicular sides and correct substitution order. Students complete:
30–42 min · Whole-class check (error-hunting). Teacher presents two incorrect solutions (e.g., students accidentally using (|\Delta x|) and (|\Delta y|) swapped, or treating the hypotenuse as a perpendicular side) and asks, “What mistake happened and how do we fix it?” Students identify the error and correct the method, using the success criteria language.
42–55 min · Independent application (distance on a grid). Teacher gives a clear problem set on coordinates requiring distance calculations and one multi-step justification. Students work individually, then confirm one answer with a partner. Students solve:
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