
Maths • 30 • 20 students • Created with AI following Aligned with New Zealand Curriculum
Free PDF · we'll email you a copy
Calculus for NCEA Level 2 Students: investigate a realistic optimisation problem by sketching a function, finding its derivative, and using the derivative to identify and justify the maximum or minimum value. Present the solution as an annotated graph with clear algebraic reasoning, following the style of an NCEA internal assessment response.
Students investigate a realistic optimisation problem: designing a rectangular animal pen beside a straight river, using 40 m of fencing for three sides. They model the area as a function, sketch the graph, differentiate, and justify the maximum area in an annotated, NCEA-style response.
Students will:
I can:
0–4 min · Hook and prediction. Teacher opens the optimisation hook and lesson sequence with the question: “Using 40 m of fencing for three sides of a pen beside a river, what dimensions create the greatest area?” Students sketch a possible design, estimate dimensions, and briefly share their prediction with a partner.
4–9 min · Build the model. Teacher uses the labelled pen diagram and modelling prompts to establish (x) as the width perpendicular to the river and (y) as the fenced length parallel to the river. Guide students to write (2x+y=40), rearrange to (y=40-2x), and form [ A(x)=xy=x(40-2x)=40x-2x^2. ] Students copy the diagram, state the realistic domain (0<x<20), and explain what (A(x)) represents.
9–15 min · Calculus demonstration. Teacher models the NCEA-style chain: [ A'(x)=40-4x,\qquad A'(x)=0 ] [ 40-4x=0\Rightarrow x=10. ] Use the derivative explanation and worked example to connect the derivative with gradient: at the maximum, the graph has a horizontal tangent. Students complete missing steps on the optimisation response worksheet and calculate (y=40-2(10)=20), then (A(10)=200\text{ m}^2).
15–22 min · Graph and justify. Teacher displays the annotated graph instructions and asks students to sketch (A(x)=40x-2x^2) on suitable axes. Require labels for the intercepts ((0,0)) and ((20,0)), the vertex ((10,200)), the domain, and the contextual meaning of the vertex. Students annotate their worksheet graph and justify that the point is a maximum using either the downward-opening quadratic or a sign change in (A'(x)): positive before (x=10), negative after (x=10).
22–27 min · NCEA response refinement. Teacher presents a model conclusion through the response checklist and peer-review prompt. Students swap work with a partner and check: variables defined, function formed, derivative shown, stationary point found, nature justified, units included, and conclusion linked to the pen. Students improve one line of algebra and one explanatory sentence.
27–30 min · Exit check. Teacher uses the plenary and exit questions to ask: “Why is (x=10) not merely a possible width, but the width that maximises area?” Students complete the final question on the worksheet: “State the maximum area, the dimensions, and one reason the result is a maximum.” Collect responses to identify misconceptions.
Join thousands of teachers using Kuraplan AI to create personalized lesson plans that align with Aligned with New Zealand Curriculum in minutes, not hours.
Created with Kuraplan AI
Generated using openai/gpt-5.6-luna
🌟 Trusted by 1000+ Schools
Join educators across New Zealand