Magnetic Fields and Charges
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Magnetic Fields and Charges
WALT & Success Criteria
WALT: We are learning to determine the direction and magnitude of the magnetic force on moving charges and to use the right-hand rule correctly.
Success criteria: I can (1) apply F = qvB sinθ for magnitudes, (2) use the right-hand rule (and reverse for negative charges) to state direction, and (3) explain why magnetic forces do no work.
Differentiation: Provide a step-by-step right-hand rule diagram for students who need more support; give numeric prompts for calculation questions.
Extension: Derive the radius r = mv/(qB) for a charged particle in uniform B and calculate a numerical example.
Dyslexia-friendly reading options: Use a ruler or finger to track each line; read questions aloud and underline key words (velocity, field direction, positive/negative).
📚 Part 1: Multiple Choice & Concept Check
✏️ Part 2: Short Answers & Worked Problems
🔑 TEACHER ANSWER KEY
Explanation: Using the right-hand rule: fingers point right (velocity), curl upward (magnetic field), thumb points into the page (force direction).
Explanation: The magnetic force F = q(v × B) is always perpendicular to both v and B vectors due to the cross product.
Explanation: Use right-hand rule for positive charge (gives out of page), then reverse for negative charge = into the page.
✓ Magnitude is F = qvB sinθ.
✓ Reversing velocity reverses the force direction.
✗ Magnetic forces can change the kinetic energy of a charged particle. (FALSE - magnetic forces do no work)
✗ A stationary charge in a magnetic field experiences a magnetic force. (FALSE - v = 0, so F = 0)
Working:
F = qvB sinθ
F = (1.60×10⁻¹⁹ C)(3.0×10⁶ m/s)(0.25 T)(sin 90°)
F = (1.60×10⁻¹⁹)(3.0×10⁶)(0.25)(1)
F = 1.2 × 10⁻¹³ N
Explanation: Using right-hand rule: fingers point up (velocity), curl into page (B-field), thumb points right. Since electrons are negative, reverse this direction = force points left. Alternative: Use left-hand rule directly for negative charges.
Magnetic force is always perpendicular to velocity, so F·v = 0. Since work = F·d = F·v·t, no work is done. The magnetic force cannot change the kinetic energy of the particle, only its direction of motion.
• Bar magnet with N and S labeled
• Curved field lines from N to S (outside magnet)
• Positive charge near north pole with rightward velocity arrow
• Force arrow on charge pointing away from magnet (using F = q(v × B))
Accept: Clear field line patterns, correct force direction based on right-hand rule application
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